18x^2+31x-49=0

Solution for 18x^2+31x-49=0 equation:

18x^2+31x-49=0

a = 18; b = 31; c = -49;
Δ = b2-4ac
Δ = 312-4·18·(-49)
Δ = 4489
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4489}=67$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(31)-67}{2*18}=\frac{-98}{36}
=-2+13/18
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(31)+67}{2*18}=\frac{36}{36}
=1
$